We might have an initial value problem, but if we use an integrating factor we can find a solution. Facebook Tweet Favorite +
Hey, girl, you must be a parabolic asymptote, because you do real interesting things to the behavior of my functions. Facebook Tweet Favorite +
I wish i was your second derivative so I could investigate your concavities. Facebook Tweet Favorite +
Girl, you must be the corresponding y in the codomain of an argument x in a one to one function, because you’re unique. Facebook Tweet Favorite +
Hey baby, hopefully you don’t think I am being obtuse, but you sure are acute. I bet if we got together it would be pretty complementary. Facebook Tweet Favorite +
Hey girl, you must be asking me to evaluate the area under a curve for an unbounded region of x, because my integral’s not the only thing that wants to get improper. Facebook Tweet Favorite +
Hey girl. Are you a 5×5 matrix inversion? Because I wanna spend way too much time with you and probably make a mistake or two. Facebook Tweet Favorite +